Best Answer
Well, first let´s convert to standard units (m/s)6mph=2.68m/s
12mph=5.36m/s
The power of a wind turbine can be expressed as:
P=(Betz factor) x (air density) x (area) x (windspeed)³
With
Betz factor=0.47 for modern 3-blades turbines
Air density=0.0012 tonne/m³
Area= (Pi x r²)
Windspeed in m/s
-------------------------
All factors being constant:
P1/P2 = (5.36)³/(2.68)³ =154/19.3 = 8 times higher
Other Answers (3)
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i%26#039;ve always heard the energy goes as the square of the wind speed, so i would think four times the power. But if that equation is right, and those other factors do not change with wind speed, then 8 times would be right.
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That depends on several things including air density.
Basically, given the same density, wind force progresses by the %26#039;square%26#039; (twice the speed gives 4 times the power), rather than simply doubling for double the speed. -
I cannot provide a better answer than N, however from the viewpoint of a commercial grade wind turbine, a 6 mph wind would not produce energy, while a 12 mph wind would.
